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X^2+2X-14.5=0
a = 1; b = 2; c = -14.5;
Δ = b2-4ac
Δ = 22-4·1·(-14.5)
Δ = 62
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{62}}{2*1}=\frac{-2-\sqrt{62}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{62}}{2*1}=\frac{-2+\sqrt{62}}{2} $
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